{"id":1293,"date":"2011-09-30T07:24:29","date_gmt":"2011-09-30T07:24:29","guid":{"rendered":"http:\/\/gigihfordanama.wordpress.com\/?p=1293"},"modified":"2012-08-08T00:08:06","modified_gmt":"2012-08-08T00:08:06","slug":"chapter-data-signal","status":"publish","type":"post","link":"https:\/\/dosen.unila.ac.id\/gigih\/2011\/09\/30\/chapter-data-signal\/","title":{"rendered":"Chapter Data &amp; Signal"},"content":{"rendered":"<p>Tugas\u00a0 Chapter Data &amp; Signal, saya kebagian membahas 4 soal ini.<\/p>\n<p><strong><span style=\"text-decoration:underline\">Questions :<\/span><\/strong><\/p>\n<ul>\n<li>Draw an example signal (similar to those shown in figure 2-12) using NRZI in which the signal never changes for 7 bits. What does the equivalent differential manchester encoding look like ?<\/li>\n<li>Twenty four voice signals are to be transmitted over a single high speed telephone line. what is the bandwidth required (in bps) if the standard analog to digital sampling rate is used and each sample is converted into an 8-bit value?<\/li>\n<li>Draw or give an example of a signal for each of the following conditions: the baud rate is equal to the bit rate, the baud rate is greater than the bit rate, and the baud rate is less than the bit rate.<\/li>\n<li>Using shannon\u2019s theorem, calculate the data transfer rate given the following information : signal\u00a0\u00a0 frequency = 10000 hz, signal power = 5000 watts, noise power = 230 watts.<\/li>\n<\/ul>\n<p><!--more--><\/p>\n<ol>\n<li>untuk NRZ-I, pemetaan data biner menjadi physical signal dengan persyaratan sebagai berikut :\n<ol>\n<li>Bernilai 1 apabila ada transisi physical signal (<em>low<\/em> ke <em>high<\/em> atau <em>high<\/em> ke <em>low<\/em>)<\/li>\n<li>Bernilai 0 apabila tidak ada transisi physical signal<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<p>Sehingga untuk signal yang tidak berubah selama 7 bit adalah :<\/p>\n<p style=\"text-align:center\"><a href=\"http:\/\/gigihfordanama.files.wordpress.com\/2011\/09\/1.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-1294\" style=\"border:4px solid black\" src=\"http:\/\/gigihfordanama.files.wordpress.com\/2011\/09\/1.jpg?w=300\" alt=\"\" width=\"466\" height=\"162\" \/><\/a><\/p>\n<p style=\"text-align:justify\">Untuk encoding Differential Manchester akan selalu ada transisi pada pertengahan interval dengan prasyarat adalah tidak mempersoalkan antara bit 1 dan bit 0 namun lebih menekankan pada transisi di awal interval, apabila ada transisi di awal interval maka nilai 0 akan ditransmisikan, apabila tidak ada transisi diawal interval, maka nilai 1 akan ditransmisikan.<\/p>\n<p style=\"text-align:center\"><a href=\"http:\/\/gigihfordanama.files.wordpress.com\/2011\/09\/21.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-1296\" style=\"border:4px solid black\" src=\"http:\/\/gigihfordanama.files.wordpress.com\/2011\/09\/21.jpg?w=300\" alt=\"\" width=\"442\" height=\"153\" \/><\/a><\/p>\n<p style=\"text-align:left\">5.\u00a0 24 buah sinyal suara dikirimkan melalui sebuah line telepon high speed, Satu sinyal disampling menjadi 8 bit,<\/p>\n<p style=\"padding-left:60px\">jumlah 24 sinyal menjadi :24\u00a0 x 8 = 192 bit<br \/>\n1\u00a0\u00a0 bit\u00a0\u00a0\u00a0\u00a0 ~ 1 second<br \/>\n192 bit\u00a0\u00a0\u00a0\u00a0 ~ 192 second<br \/>\nMaka besar bandwidth-nya : 192 bps<\/p>\n<p style=\"text-align:left\">6.\u00a0\u00a0 a. Baud rate = Bit rate<\/p>\n<p style=\"text-align:center\"><a href=\"http:\/\/gigihfordanama.files.wordpress.com\/2011\/09\/31.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-1295\" style=\"border:4px solid black\" src=\"http:\/\/gigihfordanama.files.wordpress.com\/2011\/09\/31.jpg?w=300\" alt=\"\" width=\"446\" height=\"147\" \/><\/a>Baud rate = 8 ;\u00a0 Bit rate = 8<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 b. Baud rate &gt; \u00a0 bit rate<\/p>\n<p style=\"text-align:center\"><a href=\"http:\/\/gigihfordanama.files.wordpress.com\/2011\/09\/4.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-1297\" style=\"border:4px solid black\" src=\"http:\/\/gigihfordanama.files.wordpress.com\/2011\/09\/4.jpg?w=300\" alt=\"\" width=\"442\" height=\"115\" \/><\/a>Baud rate = 16; Bit rate = 8<\/p>\n<p>\u00a0\u00a0 c. Baud rate &lt;\u00a0 bit rate<\/p>\n<p style=\"text-align:center\"><a href=\"http:\/\/gigihfordanama.files.wordpress.com\/2011\/09\/5.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium wp-image-1298\" style=\"border:4px solid black\" src=\"http:\/\/gigihfordanama.files.wordpress.com\/2011\/09\/5.jpg?w=300\" alt=\"\" width=\"437\" height=\"123\" \/><\/a>Baud rate = 1; Bit rate = 8<\/p>\n<p>22.<\/p>\n<p style=\"padding-left:30px\">Signal frekuensi = 10000 hz<br \/>\nSignal power\u00a0 = 5000 Watt<br \/>\nNoise power\u00a0 =\u00a0 230 Watt<br \/>\nData rate =\u00a0 f . Log2 ( 1 + S\/N)<br \/>\n= (10000) * (log2 (1 + 5000\/230)<br \/>\n= (10000) * ( log2 22,74)<br \/>\n= 10000 * ( log 22,74)\/(0,301)<br \/>\n= 10000 * 1,36\/0,301<br \/>\n= 43767,4 bps<br \/>\n<strong>= 43,77 kbps<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Tugas\u00a0 Chapter Data &amp; Signal, saya kebagian membahas 4 soal ini. Questions : Draw an example signal (similar to those shown in figure 2-12) using NRZI in which the signal never changes for 7 bits. What does the equivalent differential manchester encoding look like ? Twenty four voice signals are to be transmitted over a &hellip; <a href=\"https:\/\/dosen.unila.ac.id\/gigih\/2011\/09\/30\/chapter-data-signal\/\" class=\"more-link\">Continue reading<span class=\"screen-reader-text\"> &#8220;Chapter Data &amp; Signal&#8221;<\/span><\/a><\/p>\n","protected":false},"author":25,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1348,7],"tags":[219],"class_list":["post-1293","post","type-post","status-publish","format-standard","hentry","category-kiat-sukses-menjadi-seorang-network-engineer-2","category-world-of-academic","tag-chapter-data-signal"],"_links":{"self":[{"href":"https:\/\/dosen.unila.ac.id\/gigih\/wp-json\/wp\/v2\/posts\/1293"}],"collection":[{"href":"https:\/\/dosen.unila.ac.id\/gigih\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/dosen.unila.ac.id\/gigih\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/dosen.unila.ac.id\/gigih\/wp-json\/wp\/v2\/users\/25"}],"replies":[{"embeddable":true,"href":"https:\/\/dosen.unila.ac.id\/gigih\/wp-json\/wp\/v2\/comments?post=1293"}],"version-history":[{"count":0,"href":"https:\/\/dosen.unila.ac.id\/gigih\/wp-json\/wp\/v2\/posts\/1293\/revisions"}],"wp:attachment":[{"href":"https:\/\/dosen.unila.ac.id\/gigih\/wp-json\/wp\/v2\/media?parent=1293"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/dosen.unila.ac.id\/gigih\/wp-json\/wp\/v2\/categories?post=1293"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/dosen.unila.ac.id\/gigih\/wp-json\/wp\/v2\/tags?post=1293"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}